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Momentum is Still Conserved

For instance, momentum conservation must still hold, or else we would be able to tell one reference frame from another (in an absolute sense) by seeing which one got less than its share of momentum in a collision. To pursue this example, we invoke momentum conservation in a glancing collision between two identical billiard balls, as pictured below.

 

Figure: A glancing collision between two identical billiard balls of rest mass m. Ball A barely touches ball B as it passes at velocity u, imparting a miniscule transverse velocity (perpendicular to the initial velocity of A) to ball B and picking up its own transverse velocity in the process. Unprimed quantities (like and ) are measured in A's reference frame, whereas primed quantities (like and ) are measured in B's reference frame. This drawing is shown in B's reference frame.

Now, each of A and B measuresgif its own final transverse velocity (relative to the fixed dotted line along which A was originally travelling) and sends a message to the other describing the results. These messages will agree -- -- but if B measures the final transverse velocity of A in its (B's) rest frame, namely , the result will be different due to time dilation. The logic of this statement is as follows: where is the distance travelled by A (perpendicular to its original direction) in a time (as seen by B). Now, because lengths transverse to the direction of motion do not differ between reference frames. On the other hand, because of time dilation - the nearly stationary observer on B measures a longer time interval for processes in the moving frame A than are observed by A itself. Since in A's own frame, this means B ``sees'' a smaller transverse velocity for A than A ``sees'' in its own rest frame (), by a factor of :

 

Meanwhile we must have momentum conservation for the collision. This means that the transverse momentum of A as observed by B, namely , must be the same as that of B, namely . But the latter transverse velocity () is the same as that of A as measured in its own frame () and the mass of either ball measured in its own frame is just the rest mass m, so we have

 

where you may have noticed that I have started putting subscripts and primes on masses in anticipation of the conclusion that the only way to reconcile momentum conservation [Eq. (E=mc2.2)] with the relativity of transverse velocity [Eq. (E=mc2.1)] is to treat the mass - or at least the effective mass - as yet another quantity which may have different values when viewed from different reference frames. The result is obtained easily from Eq. (E=mc2.2) and Eq. (E=mc2.1):

 

where the ``'' subscript has been dropped to make Eq. (E=mc2.3) more general. In words, it reads 4.5in The effective mass of an object moving at a velocity is times its rest mass m (its mass measured in its own rest frame). That is, moving masses have more inertia!





next up previous
Next: Another Reason... Up: E=mc2 Previous: E=mc2



Jess Brewer
Fri Sep 13 11:17:01 PDT 1996